If a planet consists of a satellite whose mass and radius were both half that of the earth, the acceleration due to gravity at its surface would be (g on earth = 9.8 m/sec 2 )
Text Solution
Verified by ExpertsC
$g = \frac{\mathrm{GM}}{R^2} \therefore g \propto \frac{\mathrm{M}}{R^2}$ According to problem $\mathrm{M_p} = \frac{\mathrm{M_e}}{2}$ and $\mathrm{R_p} = \frac{\mathrm{R_e}}{2}$ $\therefore \frac{g_p}{g_e} = \left(\frac{\mathrm{M_p}}{\mathrm{M_e}}\right) \left(\frac{\mathrm{R_e}}{\mathrm{R_p}}\right)^2 = \left(\frac{1}{2}\right) \times (2)^2 = 2$ $\Rightarrow g_p = 2 g_e = 2 \times 9.8 = 19.6 \text{ m/s}^2$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems